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Grade 11IIT JEE Entrance Exam

Volume of a gas at NTP is 1.12 × 10–7 cc. The number of molecules is thus equal to:

(a) 3.01 × 1012

(b) 3.01 × 1018

(c) 3.01 × 1024

(d) 3.01 × 1030

Profile image of Radhika Batra
12 Years agoGrade 11
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2 Answers

Profile image of Kevin Nash
12 Years ago

Ans - (a)

Profile image of Abhishek Sharma
12 Years ago

1 mole of gas occupies 22.4 litres at STP
1 mole of gas contains Avogadros number of molecules = 6.022*10^23.
You have not given any units for the volume.
The answer would be (volume/22.4)*Avogadros number = (1.12*10^-7/22.4)*6.022\*10^34
= 0.3011*10^27 if volume is in litres
=0.3011*10^24 = 3.011*10^23 if volume is in m^3.
Answer is c).