IIT JEE Entrance Exam> chemistry-jee...

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Radhika Batra , 11 Years ago

Grade 11

2 Answers

Kevin Nash

Last Activity: 11 Years ago

Ans - (a)

Abhishek Sharma

Last Activity: 11 Years ago

1 mole of gas occupies 22.4 litres at STP
1 mole of gas contains Avogadros number of molecules = 6.022*10^23.
You have not given any units for the volume.
The answer would be (volume/22.4)*Avogadros number = (1.12*10^-7/22.4)*6.022\*10^34
= 0.3011*10^27 if volume is in litres
=0.3011*10^24 = 3.011*10^23 if volume is in m^3.
Answer is c).