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(1/2)g((t+1)2-t2)=24.5
44.1m is the height of the tower. assume the time taken to reach the ground 2 b (2s/g)^(1/2) (s is the height of the tower) and then put this in the equation Sn= u+(g/2)*(2n-1) which is the distance travelled the the nth second. here u=0 and take g=9.8
Dear Shubham,Distance travelled at nth sec=u + a/2(2t-1)so here 24.5=0+4.9(2t-1)hence t=3 secsit takes 3 secs to reach the bottom so height=1/2gt^2H=4.9x9=44.1 m(ANS)Regards.
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