Grade 12th PassIIT JEE Entrance Exam
equation of line jioning(0,0)and point of intersection of X2+Y2+2XY=4 , 3x2+5y2-xy=7 is
1 Answer
pvn s
The two equations above represent pair of straight lines. We can complete the square and arrive at the 4 line equatons and find their point of intersecrtion.
Simple method (by mere observation) we can say X=1&Y=1 satisfies both the equation.
therfore, Line passing through origin and (1,1) is :X=Y.
=>X=Y is the reqd line equation
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