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The Ka of unknown acid,HX,was determined to be 10^-6 calculate the [H30+] and [X-] in a 0.10M solution of HX
Dear Sandeep,
Now, Ka=10^ -6
Ka=C(alpha)^2
(where (alpha) is rate of dissociation)
Now,
C=0.01M
10^ -6=10^ -2*(alpha)square
Alpha=10^ -2
X- =H+=C(alpha)=0.01*0.01=10^-4
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