The Ka of unknown acid,HX,was determined to be 10^-6 calculate the [H30+] and [X-] in a 0.10M solution of HX

Dear Sandeep,

Now, Ka=10^ -6

Ka=C(alpha)^2

(where (alpha) is rate of dissociation)

Now,

C=0.01M

10^ -6=10^ -2*(alpha)square

Alpha=10^ -2

X- =H+=C(alpha)=0.01*0.01=10^-4

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