Flag IIT JEE Entrance Exam> coordinate geometry...
question mark

A line through A(-5,-4) meets the lines x+3y+2=0,2x+y+4=0 and x-y-5=0 at the points B,C ad D respectively. If (15/AB)^2 +(10/AC)^2=(6/AD)^2 .Find the equation of the line.

susmita maiti , 12 Years ago
Grade 11
anser 3 Answers
neeraj agarwal

Last Activity: 12 Years ago

first you take a line passing through A and having inclination m and then get a b c d and u can solve now.

u cn  see also that it will form a right angled triangle .

Ankit

Last Activity: 8 Years ago

Let slope be tanx then using parametric form of line write coordinates of B,C and D in terms of sinx and cosx. Then put points B,C,D in the lines given. You will directly get 15/AB, 10/AC and 6/AD in terms of cosx and sinx. Put in equation given to get tanx = -2/3. Slope known point known so line will be 2x + 3y + 22 = 0

saif

Last Activity: 7 Years ago

A(-5,-4)
x+5/cos@=y+4/sin@=k
x=kcos@-5,y=ksin@-4 hoga n
AB=k1,AC=k2,AD=k3
usi tarah (k1cos@-5,k1sin@-4)lies karega x+3y+2=0 pr
yha se k1 ka value aayega
k1=15/cos@+3sin@ jo isse milega
15/AB=cos@+3sin@ hoga
isi trah 10/AC=2cos@+sin@ aur 6/AD=cos@-sin@ hoga n
(15/AB)^2+(10/AC)^2=(6/AC)^2 m rkhne pr 
2+3tan@=0 aayega n
slope hogya -2/3 jo tan@ h
equatn of line y+4=tan@(x+5)
y+4=-2/3(x+5)
2x+3y+22=0 hoga jo line h

Provide a better Answer & Earn Cool Goodies

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free