If X has trigonal bipyramidal structure then its hybridisation maybe:1.sp2.sp23.sp34.None of these:)

IF X HAS TRIGONAL BIPYRAMIDAL STRUCTURE THEN IT SHOULD HAVE 5 MORE Xs.

THEN USING FORMULA 1/2(V+M-C+A) YOU WILL GET A NUMBER.

IF THE NUMBER IS 2 THEN sp.

IF THE NUMBER IS 3 THEN sp2.

IF THE NUMBER IS 4 THEN sp3.

IF THE NUMBER IS ANY OTHER THEN NONE OF THESE.

V STANDS FOR VALENCY OF X.

M STANDS FOR ADJACENT ELEMENTS EXCEPT OXYGEN.

(if oxygen comes then dont count it)

C STANDS FOR POSITIVE CHARGE.(if any then subtract)

A STANDS FOR NEGETIVE CHARGE.(if any then add the number without any sign)

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we can assume two lone pairs of electrons to be present..
hence the hybbrid state of central atom..is due to the 3 atoms on the same plane=sp2 ans

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