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If X has trigonal bipyramidal structure then its hybridisation maybe:1.sp2.sp23.sp34.None of these:)
IF X HAS TRIGONAL BIPYRAMIDAL STRUCTURE THEN IT SHOULD HAVE 5 MORE Xs. THEN USING FORMULA 1/2(V+M-C+A) YOU WILL GET A NUMBER. IF THE NUMBER IS 2 THEN sp. IF THE NUMBER IS 3 THEN sp2. IF THE NUMBER IS 4 THEN sp3. IF THE NUMBER IS ANY OTHER THEN NONE OF THESE. V STANDS FOR VALENCY OF X. M STANDS FOR ADJACENT ELEMENTS EXCEPT OXYGEN. (if oxygen comes then dont count it) C STANDS FOR POSITIVE CHARGE.(if any then subtract) A STANDS FOR NEGETIVE CHARGE.(if any then add the number without any sign) IF THIS ANSWER WAS HELPFUL THEN PLEASE ROSHAN APPROVE/LIKE THIS ANSWER. PLEASE ROSHAN BEST OF LUCK THANK YOU.
IF X HAS TRIGONAL BIPYRAMIDAL STRUCTURE THEN IT SHOULD HAVE 5 MORE Xs.
THEN USING FORMULA 1/2(V+M-C+A) YOU WILL GET A NUMBER.
IF THE NUMBER IS 2 THEN sp.
IF THE NUMBER IS 3 THEN sp2.
IF THE NUMBER IS 4 THEN sp3.
IF THE NUMBER IS ANY OTHER THEN NONE OF THESE.
V STANDS FOR VALENCY OF X.
M STANDS FOR ADJACENT ELEMENTS EXCEPT OXYGEN.
(if oxygen comes then dont count it)
C STANDS FOR POSITIVE CHARGE.(if any then subtract)
A STANDS FOR NEGETIVE CHARGE.(if any then add the number without any sign)
IF THIS ANSWER WAS HELPFUL THEN PLEASE ROSHAN APPROVE/LIKE THIS ANSWER. PLEASE ROSHAN
BEST OF LUCK
THANK YOU.
we can assume two lone pairs of electrons to be present..hence the hybbrid state of central atom..is due to the 3 atoms on the same plane=sp2 ans
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