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xsin^2x

xsin^2x

Grade:

2 Answers

Panga Mahita
37 Points
8 years ago

Is it sin2x or sin2x?? Plz tell so that I can reply u.

Manpreet Raj
29 Points
8 years ago

Abhishek Kumar,

u need to do this by using integration by parts.

u must be knowing the ILATE rule.

so, taking x as the 1st function and sin^2x as the 2nd function,

integrate it by using the formula :

integration uv dx = u ( integration v dx) - integration { (du/dx) integration v dx} dx

the answer will come out as :

( x/2 - sin4x/8 ) ( x-1)

post ur feedback

thanks

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