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xsin^2x
Is it sin2x or sin2x?? Plz tell so that I can reply u.
Abhishek Kumar, u need to do this by using integration by parts. u must be knowing the ILATE rule. so, taking x as the 1st function and sin^2x as the 2nd function, integrate it by using the formula : integration uv dx = u ( integration v dx) - integration { (du/dx) integration v dx} dx the answer will come out as : ( x/2 - sin4x/8 ) ( x-1) post ur feedback thanks
Abhishek Kumar,
u need to do this by using integration by parts.
u must be knowing the ILATE rule.
so, taking x as the 1st function and sin^2x as the 2nd function,
integrate it by using the formula :
integration uv dx = u ( integration v dx) - integration { (du/dx) integration v dx} dx
the answer will come out as :
( x/2 - sin4x/8 ) ( x-1)
post ur feedback
thanks
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