xsin^2x

Is it sin2x or sin²x?? Plz tell so that I can reply u.

Abhishek Kumar,

u need to do this by using integration by parts.

u must be knowing the ILATE rule.

so, taking x as the 1st function and sin^2x as the 2nd function,

integrate it by using the formula :

integration uv dx = u ( integration v dx) - integration { (du/dx) integration v dx} dx

the answer will come out as :

( x/2 - sin4x/8 ) ( x-1)

post ur feedback

thanks