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Grade 12IIT JEE Entrance Exam

if sinx=x/100.

then the total number of values of x are:

the answer is 63 as given in the brilliant tutorials module.

but i am not able to figure it out how .

please tell the solution asap.

Profile image of Vinayak Gupta
14 Years agoGrade 12
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3 Answers

Profile image of APURV GOEL
ApprovedApproved Tutor Answer14 Years ago

You can solve it by graphical approach approach you can think of intersection of 2 graphs y = sinx and y = x/100

now sinx remains within [-1,1] first consider positive values of x then x/100 touches 1 at 100 which comes out to be around 31.8 pie by dividing by 3.14 so if we think about the intersections there will be 32 intersections including 0 and similarly there will be 31 intersections on negative side excluding zero as we have counted it earlier.

Hence there are a total of 63 intersections.

if u have any problem in analysing there graph tell me and i will post the image of a rough diagram of the intersections.

Profile image of Vinayak Gupta
14 Years ago

thanks apurv

Profile image of Kushagra
9 Years ago
First divide x/100π by 22/7 to get 31π+9π/11So in 31π oscillations sinx will be cut at 62 pts on negative + positive side and at 0 so total =63We exclude 9π/11 because at this pt graph of y = x/100 goes above graph of sinx