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At a distance of 4,000 ft from the launch site, a spectator is observing a rocket being launched. If the rocket lifts off vertically and is rising at a speed of 600 ft/sec when it is at an altitude of 3,000 ft, how fast is the distance between the rocket and the spectator changing at that instant?

Akash Deep Goel , 14 Years ago
Grade
anser 2 Answers
Chetan Mandayam Nayakar

distance=s=√(40002+h2), rate of change of distance=ds/dt=(ds/dh)(dh/dt)=(d(√(40002+h2)/dh)(dh/dt),dh/dt=600 ft/sec

Last Activity: 14 Years ago
archit srivastava

250/3 ft/sec using 2d figure

Last Activity: 13 Years ago
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