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The coefficient of t 24 in (1+t²) 12 (1+t 12 )(1+ 24 ) is

The coefficient of t24 in (1+t²)12(1+t12)(1+24) is

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1 Answers

sushant singh
66 Points
11 years ago

gud question hemant ....

please check the solution of it 

Multiplying the last two expressions we have to find coefficient of t24in (1+t²)12(1+t12+24

t24 term will come as a sum of three terms in the expanded expression

1st term is t24 term in 1st expression multiplied by 1 in the second expression.
2nd term is t12 term in 1st expression multiplied by t12 term in the second expression.
3rd term is 1 in the first expression multiplied by t24 term in the second expression.

Coefficients of 1 and 3 terms are 1 and 1.

Coefficient of 2 term = coefficient t12 term in 1 st expression which is (1+t²)12

7th term or 6+1th term in the expansion will have t12 term

Hence coefficient of 7th term = 12C6

Therefore coefficient of t24 term will be

12C6 + 2 ...Answer...

 i think we are at solutions....

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