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Dear Prachi
Gravitational field at a distance r from the infinitely long rod with liner mass density d = 2Gd/r
here r=L and force will be field x mass
force= 2GMd/L
All the best.
AKASH GOYAL
AskiitiansExpert-IIT Delhi
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Gravitational Force is -Gm1m2 / r^2
since r is the radius and it is the prependicular distance between the rod and the point of mass M
the mass of the rod is d*V , since a rod is cylindrical the volume is pi*r*r*h and h = infinity
so mass of rod = d*infinity = infinity
Gravitational Force = - G * infinity * M / L^2
= - infinity / l^2
since infinity divided by any positive number is also infinity
= - infinity !
therefore gravitational force is - infinity
please approve if the answer is correct
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