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the gravitational force between a point like mass M and an infinitely long,thin rod of linear mass density d at a perpandicular distance L from M is ?? the gravitational force between a point like mass M and an infinitely long,thin rod of linear mass density d at a perpandicular distance L from M is ??
Dear Prachi Gravitational field at a distance r from the infinitely long rod with liner mass density d = 2Gd/r here r=L and force will be field x mass force= 2GMd/L All the best. AKASH GOYAL AskiitiansExpert-IIT Delhi Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively :Click here to download the toolbar..
Dear Prachi
Gravitational field at a distance r from the infinitely long rod with liner mass density d = 2Gd/r
here r=L and force will be field x mass
force= 2GMd/L
All the best.
AKASH GOYAL
AskiitiansExpert-IIT Delhi
Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively :Click here to download the toolbar..
Gravitational Force is -Gm1m2 / r^2 since r is the radius and it is the prependicular distance between the rod and the point of mass M the mass of the rod is d*V , since a rod is cylindrical the volume is pi*r*r*h and h = infinity so mass of rod = d*infinity = infinity Gravitational Force = - G * infinity * M / L^2 = - infinity / l^2 since infinity divided by any positive number is also infinity = - infinity ! therefore gravitational force is - infinity please approve if the answer is correct
Gravitational Force is -Gm1m2 / r^2
since r is the radius and it is the prependicular distance between the rod and the point of mass M
the mass of the rod is d*V , since a rod is cylindrical the volume is pi*r*r*h and h = infinity
so mass of rod = d*infinity = infinity
Gravitational Force = - G * infinity * M / L^2
= - infinity / l^2
since infinity divided by any positive number is also infinity
= - infinity !
therefore gravitational force is - infinity
please approve if the answer is correct
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