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the four digit no. 2652 is such that any two consecutive digits from it make a multipleof 13. another no. n has this same property, is 100 digits long and begins in a 9. the last digit of n is ? pls explain how this type of Qu are solved ?

the four digit no. 2652 is such that any two consecutive digits from it make a multipleof 13. another no. n has this same property, is 100 digits long and begins in a 9. the last digit of n is ? pls explain how this type of Qu are solved ?

Grade:10

1 Answers

Rahul askIITiansExpert.IITR
110 Points
13 years ago
such questions are solved by pure logic.

there is no set formula for them

now

which digit should come after 9

1?

right

and after 1

3

after 3?

9

after 9?

1..

so the series continues

the number is

9139139139.........upto hundred digits.

the 99th digit would 3

and hundredth? well it should be 9 right??

simple!!

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