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Dear Sir ,

In the question - no. of nuetrons emitted when 92 U 235 undergoes nuclear fission to give 54 Xe 142 and 38 Sr 90 what is the correct answer??

SANKET DASH , 14 Years ago
Grade
anser 2 Answers
Arun

Last Activity: 4 Years ago

The number of neutrons emitted when  
92
235
​ 
 U undergoes controlled nuclear fission to  
54
142
​ 
 Xe and  
38
90
​ 
 Sr is 4.
92
235
​ 
 U+ 
0
1
​ 
 n→ 
54
142
​ 
 Xe+ 
38
90
​ 
 Sr+4 
0
1
​ 
 n+energy

Vikas TU

Last Activity: 4 Years ago

Dear student 
The above explanation is not clear ….....
Please o not follow the explanation. 
We regret for inconvenience.........
Good Luck 

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