Grade 11IIT JEE Entrance Exam100ml of 20.8% BaCl2 solution and 50ml of 9.8% H2So4 sol will form Baso4 - SF 9 Years agoGrade 11
Vikas TU6 Years ago100ml of 20.8% BaCl2 solution ≡ 20.8 g BaCl250ml of 9.8% H2SO4 solution ≡ 4.9 g H2SO4BaCl2 + H2SO4 = BaSO4 + 2HCl208 g 98 g 233 g98 g H2SO4 reacts with 208 g BaCl21 g H2SO4 reacts with 208/98 g BaCl24.9 g H2SO4 reacts with 208/98 X 4.9 g BaCl2 = 10.4 g BaCl298 g H2SO4 will produce 233 g BaSO41 g H2SO4 will produce 233/98 g BaSO44.9 g H2SO4 will produce 233/98 X 4.9 g BaSO4 = 11.65 g BaSO43.9