Grade 12th passIIT JEE Entrance Exam
1².2/1! + 2².3/2! + 3².4/3! +.... +infinityA) 6e B) 7e C) 8e D) 9e
1 Answer
Arun
testing for 3 terms, (n=3)
1²/1 + (1²+2²)/2 + (1²+2²+3²)/3
= 1 + 5/2 + 14/3
= 49/6
for n = 3
a) --> (3/36)(36+45+17) = 49/6
b) --> (3/6)((4)(2) = 4 , noway!
c) --> (9+9+29) = 47 , noway!
suspicious it could be a)
test for n = 2
sum(2) = 1 + 5/2 = 7/2
a) --> (2/36)(16 + 30 +17) = 7/2
testing for n = 4
sum4 = 1+5/2+14/3+ (1^2+2^2+3^2+4^2)/4 = 15/2
using a) --> (4/36)(64 + 60 + 17) = 47/3 ≠ 15/2
1²/1 + (1²+2²)/2 + (1²+2²+3²)/3
= 1 + 5/2 + 14/3
= 49/6
for n = 3
a) --> (3/36)(36+45+17) = 49/6
b) --> (3/6)((4)(2) = 4 , noway!
c) --> (9+9+29) = 47 , noway!
suspicious it could be a)
test for n = 2
sum(2) = 1 + 5/2 = 7/2
a) --> (2/36)(16 + 30 +17) = 7/2
testing for n = 4
sum4 = 1+5/2+14/3+ (1^2+2^2+3^2+4^2)/4 = 15/2
using a) --> (4/36)(64 + 60 + 17) = 47/3 ≠ 15/2
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