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shubham surve Grade: 12
        
with what mimum speed must a particle be projetcted from origin so that it is able to pass through a given point(30m,40) g=10 mps
 
one year ago

Answers : (1)

Vikas TU
6872 Points
										
Let the speed be v and projection angle be thetha..
Then in x direcn. =>
30 = vcosthetha*t..............(1)
and
in y – direction,
40 = 0 + 0.5gt^2
t = 2root(2) seconds.
put in eqn. (1) we get,
vcosthetha =  30/2root(2) => 15/root(2)
v = 15/root(2)*cos(thetha)
For minimum v, denominator should be maximum and therfore, thetha should be minimum as it is a decreasing  function.
Hence thetha = 0 degree and
V = 15/root(2) m/s
one year ago
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