MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
with what mimum speed must a particle be projetcted from origin so that it is able to pass through a given point(30m,40) g=10 mps
 
one year ago

Answers : (1)

Vikas TU
6874 Points
							
Let the speed be v and projection angle be thetha..
Then in x direcn. =>
30 = vcosthetha*t..............(1)
and
in y – direction,
40 = 0 + 0.5gt^2
t = 2root(2) seconds.
put in eqn. (1) we get,
vcosthetha =  30/2root(2) => 15/root(2)
v = 15/root(2)*cos(thetha)
For minimum v, denominator should be maximum and therfore, thetha should be minimum as it is a decreasing  function.
Hence thetha = 0 degree and
V = 15/root(2) m/s
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 64 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details