Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
with what mimum speed must a particle be projetcted from origin so that it is able to pass through a given point(30m,40) g=10 mps
Let the speed be v and projection angle be thetha..Then in x direcn. =>30 = vcosthetha*t..............(1)andin y – direction,40 = 0 + 0.5gt^2t = 2root(2) seconds.put in eqn. (1) we get,vcosthetha = 30/2root(2) => 15/root(2)v = 15/root(2)*cos(thetha)For minimum v, denominator should be maximum and therfore, thetha should be minimum as it is a decreasing function.Hence thetha = 0 degree andV = 15/root(2) m/s
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -