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with what mimum speed must a particle be projetcted from origin so that it is able to pass through a given point(30m,40) g=10 mps
Let the speed be v and projection angle be thetha..Then in x direcn. =>30 = vcosthetha*t..............(1)andin y – direction,40 = 0 + 0.5gt^2t = 2root(2) seconds.put in eqn. (1) we get,vcosthetha = 30/2root(2) => 15/root(2)v = 15/root(2)*cos(thetha)For minimum v, denominator should be maximum and therfore, thetha should be minimum as it is a decreasing function.Hence thetha = 0 degree andV = 15/root(2) m/s
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