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which one of the following transitions in a hydrogen atom will emit the photon of shortest wavelength n = 2 to n = 1 n = 6 to n = 5 n = 6 to n = 1 n = 5 to n = 4
shortest wavelength implies maximum energy difference. Maximum energy difference comes when electrons are transferred from n = 2 to n = 1energy in any orbital = -13.6/ n2
wave number Shortest wavelength will correspond to largest .For n=2 to n=1,Similarly for n=6 to n=5, For n=6 to n=1For n=5 to 4So n=6 to 1 is the answer.Please approve the answer if you are helped.
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