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When the tension on a wire is 4N its length is l 1 . When the tension on the wire is 5N its length is l 2 . Find its natural length

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4 years ago

Vikas TU
14146 Points
```							let x1 and x2 be the extension with 4N and 5N respectively.then the eqns. would be:4 = k * x1  and  5  = k * x2and let l be the natural length of the wire.Hence,x1 + l = l1andx2 + l = l2 put x1 and x2 values in Tensions after dividing them respectively:Therefore,4/5 = x1/x2 = > (l1 – l)/(l2 – l)4l2 – 4l = 5l1 – 5ll = 5l1 – 4l2hence would be the nautral length.
```
4 years ago
Roshan agrawal
19 Points
```							L = (T2l1 - T1l2)/T2 - T1 Where  T2 and T1 = tension l1 and l2 =   length    This can be solved by equate the modules of elasticity that young`s modules
```
2 years ago
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