Vikas TU
Last Activity: 8 Years ago
let x1 and x2 be the extension with 4N and 5N respectively.
then the eqns. would be:
4 = k * x1 and 5 = k * x2
and let l be the natural length of the wire.
Hence,
x1 + l = l1
and
x2 + l = l2
put x1 and x2 values in Tensions after dividing them respectively:
Therefore,
4/5 = x1/x2 = > (l1 – l)/(l2 – l)
4l2 – 4l = 5l1 – 5l
l = 5l1 – 4l2
hence would be the nautral length.