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What is the expected period of beats formed when two tuning forks sound simultaneously and have the frequencies f1= 250Hz and 242Hz?

rishav kumar , 12 Years ago
Grade 9
anser 2 Answers
Askiitians Tutor Team

When two tuning forks with different frequencies are sounded together, they create a phenomenon known as beats. The beat frequency is determined by the difference in frequencies of the two sound sources. In your case, we have two tuning forks with frequencies of 250 Hz and 242 Hz. Let's break down how to calculate the expected period of the beats formed.

Understanding Beat Frequency

The beat frequency can be calculated using the formula:

f_beat = |f1 - f2|

Where:

  • f1 = frequency of the first tuning fork (250 Hz)
  • f2 = frequency of the second tuning fork (242 Hz)

Calculating the Beat Frequency

Now, let's plug in the values:

f_beat = |250 Hz - 242 Hz| = |8 Hz| = 8 Hz

This means that the beat frequency is 8 Hz, which indicates that the sound will fluctuate 8 times per second as the two frequencies interfere with each other.

Determining the Period of Beats

The period of the beats is the reciprocal of the beat frequency. The period (T) can be calculated using the formula:

T_beat = 1 / f_beat

Calculating the Period

Substituting the beat frequency into the formula gives us:

T_beat = 1 / 8 Hz = 0.125 seconds

This means that the period of the beats formed when the two tuning forks sound simultaneously is 0.125 seconds.

Visualizing the Concept

To visualize this, imagine two waves traveling through the air. When they are in sync, they amplify each other, creating a louder sound. However, as they drift out of sync due to their frequency difference, they will periodically cancel each other out, resulting in a fluctuating sound intensity. This fluctuation occurs at the beat frequency, which we calculated to be 8 Hz, leading to a period of 0.125 seconds.

In summary, when you strike both tuning forks, you will hear a sound that alternates in loudness every 0.125 seconds due to the interference of the two frequencies. This is a fascinating example of wave behavior and sound interaction! If you have any further questions about sound waves or related topics, feel free to ask.

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Last Activity: 10 Months ago
Askiitians Tutor Team

When two tuning forks with different frequencies sound together, they create a phenomenon known as beats. The beat frequency is the difference between the two frequencies, and it tells us how often the sound waves will interfere with each other, resulting in a variation in loudness. In your case, we have two frequencies: f1 = 250 Hz and f2 = 242 Hz. Let's break down how to find the beat frequency and the expected period of the beats.

Calculating the Beat Frequency

The beat frequency (f_beat) can be calculated using the formula:

f_beat = |f1 - f2|

Substituting the given frequencies:

f_beat = |250 Hz - 242 Hz| = 8 Hz

Understanding the Implications

This means that the sound waves from the two tuning forks will interfere with each other 8 times per second, creating a beat effect that you can hear as a fluctuation in volume. The sound will get louder and softer in a rhythmic pattern as the waves align and misalign.

Finding the Period of the Beats

The period (T) of the beats is the time it takes for one complete cycle of the beat to occur. It is the inverse of the beat frequency:

T = 1 / f_beat

Now, substituting the beat frequency we calculated:

T = 1 / 8 Hz = 0.125 seconds

Visualizing the Concept

To visualize this, think of two people clapping their hands at different rates. If one person claps 250 times a minute and the other claps 242 times, you will hear a pattern of loud and soft claps. The difference in their clapping rates creates a rhythm that repeats every 0.125 seconds.

Summary of Key Points

  • The beat frequency is 8 Hz, indicating how often the beats occur.
  • The period of the beats is 0.125 seconds, which is the time between each beat.

In essence, when you hear the two tuning forks sound together, you will experience a rhythmic fluctuation in volume every 0.125 seconds due to the interference of their sound waves. This is a fascinating example of wave behavior and how different frequencies interact with one another!

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Last Activity: 10 Months ago
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