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What is the de Broglie wavelength associated with an electron, accelerated through a potential differnece of 100 volts?

Jayant Kumar , 12 Years ago
Grade 11
anser 1 Answers
Apoorva Arora
KE= 100 eV
So,P=\frac{h}{\lambda }
\lambda =\frac{h}{P}
\lambda =\frac{h}{\sqrt{2mKE}}
Putting the values,
\lambda = 1.227 A^{0}
Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
Last Activity: 11 Years ago
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