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what is the capacitance when capacitor passes a current of 31.43 ma when supplied with 40 v ac with a frequency of 1000hz?
Voltage across the capacitance = > 40 V.Hence, 40 = 31.43 x 10^-3/(2*pi*1000)*CWe get,C = 0.000125 x 10^-3 Farador C = 125 nF.
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