Grade 10General Physics
what is Stefan - Boltzmann’s Law.it explain
what is Stefan - Boltzmann’s Law.it explain
11 Answers
mahendra
Approved Tutor Answer10 Years agoa) If a black body at absolute temperature T is surrounded by an enclosure at absolutetemperature To , then the rate of loss of heat energy by radiation per unit area is given by.E = σ (T 4 − T0 4 )b) For any hot body, E = σ Ae(T 4 − T0 4 )Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
venky
he Stefan–Boltzmann law, also known as Stefan's law, describes the power ... Specifically, the Stefan–Boltzmann law states that the total energy radiated per ..
mahendra
a) If a black body at absolute temperature T is surrounded by an enclosure at absolute
temperature To , then the rate of loss of heat energy by radiation per unit area is given by.
E = σ (T 4 − T0 4 )
b) For any hot body, E = σ Ae(T 4 − T0 4 )
Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
temperature To , then the rate of loss of heat energy by radiation per unit area is given by.
E = σ (T 4 − T0 4 )
b) For any hot body, E = σ Ae(T 4 − T0 4 )
Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
venky
rey harinath approve chey
salvathshaik
If a black body at absolute temperature T is surrounded by an enclosure at absolutetemperature To , then the rate of loss of heat energy by radiation per unit area is given by.E = σ (T 4 − T0 4 )b) For any hot body, E = σ Ae(T 4 − T0 4 )Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
mahendra
a) If a black body at absolute temperature T is surrounded by an enclosure at absolutetemperature To , then the rate of loss of heat energy by radiation per unit area is given by.E = σ (T 4 − T0 4 )b) For any hot body, E = σ Ae(T 4 − T0 4 )Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
salvathshaik
If a black body at absolute temperature T is surrounded by an enclosure at absolutetemperature To , then the rate of loss of heat energy by radiation per unit area is given by.E = σ (T 4 − T0 4 )b) For any hot body, E = σ Ae(T 4 − T0 4 )Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
mahendra
a) If a black body at absolute temperature T is surrounded by an enclosure at absolutetemperature To , then the rate of loss of heat energy by radiation per unit area is given by.E = σ (T 4 − T0 4 )b) For any hot body, E = σ Ae(T 4 − T0 4 )Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
pa1
a) If a black body at absolute temperature T is surrounded by an enclosure at absolute
temperature To , then the rate of loss of heat energy by radiation per unit area is given by.
E = σ (T 4 − T0 4 )
b) For any hot body, E = σ Ae(T 4 − T0 4 )
Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
temperature To , then the rate of loss of heat energy by radiation per unit area is given by.
E = σ (T 4 − T0 4 )
b) For any hot body, E = σ Ae(T 4 − T0 4 )
Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
sathish
a) If a black body at absolute temperature T is surrounded by an enclosure at absolute temperature To , then the rate of loss of heat energy by radiation per unit area is given by. E = σ (T 4 − T0 4...
Surendra
a) If a black body at absolute temperature T is surrounded by an enclosure at absolutetemperature To , then the rate of loss of heat energy by radiation per unit area is given by.E = σ (T 4 − T0 4 )b) For any hot body, E = σ Ae(T 4 − T0 4 )Where ‘e’ is the emissive power and ‘A’ is the area of cross-section of the hot body
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