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What happens to the force between two charges if the distance between them is (a) halved (b) doubled.

What happens to the force between two charges if the distance between them is (a) halved (b) doubled.

Grade:upto college level

1 Answers

Apoorva Arora IIT Roorkee
askIITians Faculty 181 Points
7 years ago
The force between two charges is given by
F=\frac{Kq_{1}q_{2}}{r^{2}}
so if the distance is halved
F'=\frac{Kq_{1}q_{2}}{(r/2)^{2}}=4F
so the force increases four times
and, when the distance is doubled
F'=\frac{Kq_{1}q_{2}}{(2r)^{2}}=F/4
and so the force decreases 4 times.

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