Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Water droplets are falling from celing of a room at equal intervals of time . Assume downward acceleration 10 m/s at the time when 4th drop is about to fall.Find the ratio of distances between consecutive drops.`
one year ago

Srijan Srivastava
30 Points
```							u=0m/s
let the distance travelled by 1st drop be S1 in time t seconds
so the distannce travelled by 2nd drop be S2 in time t/2 seconds due to equal intervals.
S = ut + (1/2)at2
hence,  S1 = 0 + ½ at2
S2 = 0 + ½ a(t/2)2
S1:S2 = 4:1
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions