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`        water drop fall from a tap on the floor 5 M below at regular intervals of time the first drop is dragging The Frozen V begin to fall the height at which the third eye drop will be from ground at the instant win the first drop strike the ground will be`
one year ago

Arun
22958 Points
```							Dear Anuj  Height of tap = 5m and (g) = 10 m/sec2. For the first drop, 5 = ut +  gt 2 = (0 × t) +  × 10 t2 v= 5t2 or t2 = 1 or t = 1. It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec. Distance covered by the second drop in 0.5 sec           = (0.5)2 = 1.25m         Therefore, distance of the second drop above the ground = 5 - 1.25 = 3.75 m.  RegardsArun (askIITians forum expert)
```
one year ago
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