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Grade: 12th pass
        water drop fall from a tap on the floor 5 M below at regular intervals of time the first drop is dragging The Frozen V begin to fall the height at which the third eye drop will be from ground at the instant win the first drop strike the ground will be
10 months ago

Answers : (1)

Arun
14736 Points
							
Dear Anuj
 
 

Height of tap = 5m and (g) = 10 m/sec2.

 

For the first drop, 5 = ut +  gt 2

 

= (0 × t) +  × 10 t2 v= 5tor t= 1 or t = 1.

 

It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

 

Distance covered by the second drop in 0.5 sec

 

 

 

        = (0.5)2 = 1.25m

 

        Therefore, distance of the second drop above the ground

 

= 5 - 1.25 = 3.75 m.

 

 

Regards

Arun (askIITians forum expert)

10 months ago
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