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Grade: 12th pass
        water drop fall from a tap on the floor 5 M below at regular intervals of time the first drop is dragging The Frozen V begin to fall the height at which the third eye drop will be from ground at the instant win the first drop strike the ground will be
one year ago

Answers : (1)

22958 Points
Dear Anuj

Height of tap = 5m and (g) = 10 m/sec2.


For the first drop, 5 = ut +  gt 2


= (0 × t) +  × 10 t2 v= 5tor t= 1 or t = 1.


It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.


Distance covered by the second drop in 0.5 sec




        = (0.5)2 = 1.25m


        Therefore, distance of the second drop above the ground


= 5 - 1.25 = 3.75 m.




Arun (askIITians forum expert)

one year ago
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