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Height of tap = 5m and (g) = 10 m/sec2.
For the first drop, 5 = ut + gt 2
= (0 × t) + × 10 t2 v= 5t2 or t2 = 1 or t = 1.
It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.
Distance covered by the second drop in 0.5 sec
= (0.5)2 = 1.25m
Therefore, distance of the second drop above the ground
= 5 - 1.25 = 3.75 m.
Regards
Arun (askIITians forum expert)
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