Vector basic question but tricky forore.details lease check the attached image
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General Physics> Vector basic question but tricky forore.d...
1 AnswersSamyak Jain
Last Activity: 5 Years ago
Let speed of particle at t = 1s be u and that of particle at t = 2s be v.
uniformly accelerated in the three parts.
Average velocity is the ratio of total displacement to the time for which dispalcement has occured.
And for uniformly accelerated motion, we know, v = u + at ...(1) and v2 = u2 + 2as ...(2)
We need to calculate s/t. From (2), s = (v2 – u2)/2a 
s/t = (v2 – u2)/2at
s/t = (v2 – u2)/2(v – u) = (v – u)(v + u)/2(v – u) = (u + v)/2,
i.e. the average velocity is the mean of initial and final velocities for uniformly accelerated motion.
(You can remember this as a result.)
So for the first part, average velocity = V1 = (0 + u) / 2 i.e. u = 2 V1.
Similarly, V2 = (u + v)/2 = (2 V1 + v) /2 v = 2V2 – 2V1
v = 2(V2 – V1).
For last one second, average velocity = (v + 0)/2 = v/2 = 2(V2 – V1) / 2
= V2 – V1 .
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