Flag General Physics> Using the Bohr’s model calculate the spee...
question mark

Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1, 2, and 3 levels. (b) Calculate the orbital period in each of these levels.

Jayant Kumar , 11 Years ago
Grade 11
anser 1 Answers
Raghav Pareek

Last Activity: 7 Years ago

Let, electron of hydrogen atom at ground state n1=1v1=e2/n14πε0(h/2π)= e2/2ε0h where, e = 1.6 x 10-19C, ε0= 8.85 x 10-12 /NC2/m2, h = 6.62 x 10-34 Jsthen,v1=e2/2ε0h = (1.6 x 10-19)2/ 2x2x8.85 x 10-12 x 6.62 x 10-34 = 1.09 x 106 m/sfor n3 = 3,then,v1=e2/ n32ε0h = (1.6 x 10-19)2/ 3x2x8.85 x 10-12 x 6.62 x 10-34 = 7.27 x 106 m/s (b) Let T1 = orbital period of electron, n1=1Then, Orbital period is related to orbital speedT1 = 2πr1/v1 where, Radius of the orbit (r1) = n12 h2 ε0/πme2Where, e = 1.6 x 10-19C, ε0= 8.85 x 10-12 /NC2/m2, h = 6.62 x 10-34 JsMass of an electron (m) = 9.1 x10-31 KgTherefore,T1 = 2πr1/v1 = 2xπ x (1)2 x (6.62 x 10-34)2 x 8.85 x 10-12/2.18x106x π x 9.1 x10-31 x(1.6 x 10-19)2 = 15.27 x 10-27 = 1.52 x 10-16 sFor level n2=2T2 = 2πr2/v2 = 2xπ x (2)2 x (6.62 x 10-34)2 x 8.85 x 10-12/1.09x106x π x 9.1 x10-31 x(1.6 x 10-19)2 = 1.22 x 10-15 sFor level n3=3T3 = 2πr3/v3 = 2xπ x (3)2 x (6.62 x 10-34)2 x 8.85 x 10-12/7.27x106x π x 9.1 x10-31 x(1.6 x 10-19)2 = 4.12 x 10-15 sHence, the orbit period in each level is 1.527 x 10-16 s, 1.22 x 10-15 s, 4.12 x 10-15 s respectively.

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...