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Two vectors have magnitudes 2 m and 3 m. The angle between them is 60°. Find (a) The scalar product of the two vectors, (b) The magnitude of their vector product.
Let the magnitudes of two vectors be, a=2 m and b=3 mθ= angle between the vectors =60°.(a) The scalar product of the twovectors is given by abCosθ= 2.3.Cos60° = 3 m².(b) The magnitude of their vector product is = abSinθ =2.3.Sin60° =2.3.√3/2 =3√3 m²
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