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Grade: 11

                        

Two vector of same magnitude are inclined at angle theta the magnitude of their difference be?

3 years ago

Answers : (1)

Dev r
39 Points
							
Short answer:  (2a2(1+cos(x))^(1/2) where a is their magnitude and x is the nangle between them.
Long answer:  Suppose th vectors are A and B.
Thier magnitudes are same i.e. |A|=a and |B|=a.
Let the angle between them be x.
The magnitude of -B would be the same as B but in the opposite direction,
So B and -B are in a straight line but pointing in opposite directions so the angle between A and -B is (180-x).
 
Therefore A-B=A+(-B)=(|A|2+|B|2+2*|A|*|B|*cos(180-x))^(1/2)
 
3 years ago
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