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Two vector of same magnitude are inclined at angle theta the magnitude of their difference be?
Two vector of same magnitude are inclined at angle theta the magnitude of their difference be?

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3 years ago

Dev r
39 Points
```							Short answer:  (2a2(1+cos(x))^(1/2) where a is their magnitude and x is the nangle between them.Long answer:  Suppose th vectors are A and B.Thier magnitudes are same i.e. |A|=a and |B|=a.Let the angle between them be x.The magnitude of -B would be the same as B but in the opposite direction,So B and -B are in a straight line but pointing in opposite directions so the angle between A and -B is (180-x). Therefore A-B=A+(-B)=(|A|2+|B|2+2*|A|*|B|*cos(180-x))^(1/2)
```
3 years ago
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