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        Two swimmer's A and B initially on the opposite banks of a river are situated exactly opposite to each other. They can swim with speeds vA = v and vB = v in still water. They start swimming simultaneously at angles A = 30° and B =  with respect to the river. Calculate the time after which they will meet. (given 'd' = width of the river ; v = speed of the river.)
2 years ago

## Answers : (2)

Arun
23330 Points
							Dear Varsha Check if its answer is $\sqrt$3 d /2v If it's correct.then I will tell you the solution. RegardsArun (askIITians forum expert)

2 years ago
Joe Allan
13 Points
							Dear Varsha,Let's take component of velocity of both swimmers along the line joining them(LJT),So.Va along LJT =√3v/2Vb along LJT= vcos$\Theta$/√3And from condition for collision we get that relative velocity along river should be zeroSince relative velocity must be only along line joining them,Va along river =v- v/2=v/2Vb along river =v(1-sin$\Theta$/√3)=>V/2 -v(1-sin$\Theta$/√3)=01/2=sin$\Theta$/√3$\Theta$=π/3Now coming to line joining themd=(√3v/2+ v/√3cos$\Theta$)td=(√3v/2+ v/2√3)td=(4v/2√3)tt=√3d/2v

one year ago
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