Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 10^7 Pa? Assume that each rivet is to carry one quarter of the load.

When the riveted strip is subjected to a stretching load W,
the tensile force in each strip provides the shearing force
 on the four rivets.Since the load is shared uniformly,each
 rivet is under a shear
2 -3 2
max max 7
max
 force of W/4.
Diameter of rivet =6 mm
(D) (6 10 ) Area of rivet on which shear force acts,A= 4 4
Now,Maximum shear stress on each rivet
Maximum Shearing force W /4 W = = =6.9 10 Pa Area A 4A
( W 4
π π
π
×
=
= ×
⇒ = ×
-3 2 6 10 ) 7 6.9 10 4
 =7.8 kN