Kushagra Madhukar
Last Activity: 4 Years ago
Hello student
As mentioned the spheres are connected by a wire, thus they will acquire equal electrical potential
Since, the distance between the two spherical conductors is 5cm which is very much greater than the radii of the spheres (1mm, 2mm)
Hence the potential of one body due to the other can be ignored.
here, r1 = 1mm ; r2 = 2mm
Now,
V1 = V2
or, kQ1/r1 = kQ2/r2
or, Q2/Q1 = r2/r1 = 2/1
Now, the ratio of electrical fields at the surface of spheres is
EA/EB = E1/E2 = (kQ1/r12)/(kQ2/r22)
= (Q1/Q2) x (r22/r12)
= (r1/r2) x (r22/r12)
= (r2/r1)
= 2:1
Hope it helps
Regards,
Kushagra