Subhashree
Last Activity: 5 Years ago
Here let us first consider it for one satellite...
Potential energy U=-GMm/r
Kinetic energy=+GMm/2r
So total energy= -GMm/r+GMm/2r
. = -GMm/2r
Now for two satellite ...TE=2GMm/2r
= -GMm/r.
But since it undergoes inelastic collision..mv1+mv2=(m+m)v.
Since they move in opposite direction v1=-v2 ..so
Net v =0.. so no Kinetic energy only potential energy exist
Thus TE=-GM(2m)/r