Question icon
Grade 11General Physics

two rings of same mass and radius are placed such that their centers are at a common point and their planes are perpendicular to each other. the value of I about an axis passing through the centers and perpendicular to the plane of one ring is??

Profile image of reshma chauhan
12 Years agoGrade 11
Answers icon

1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer0 Years ago

To determine the moment of inertia of two rings with the same mass and radius, positioned such that their centers coincide and their planes are perpendicular to each other, we can use the principles of rotational dynamics. The moment of inertia is a measure of an object's resistance to changes in its rotation about an axis. Let's break this down step by step.

Understanding Moment of Inertia

The moment of inertia (I) of a single ring about an axis passing through its center and perpendicular to its plane is given by the formula:

  • I = m * r²

where m is the mass of the ring and r is its radius. For our case, we have two rings, each with mass m and radius r.

Calculating the Moment of Inertia for One Ring

For one ring, the moment of inertia about the axis perpendicular to its plane is:

  • I₁ = m * r²

Considering Both Rings

Since the two rings are positioned such that their centers are at the same point and their planes are perpendicular, we can treat their moments of inertia about the chosen axis independently. The total moment of inertia about the axis passing through the centers and perpendicular to the plane of one ring is simply the sum of the moments of inertia of both rings.

Applying the Parallel Axis Theorem

In this specific configuration, we don't need to apply the parallel axis theorem because both rings share the same center. Therefore, the total moment of inertia (I_total) can be calculated as:

  • I_total = I₁ + I₂

Substituting the values for both rings:

  • I_total = m * r² + m * r²
  • I_total = 2 * m * r²

Final Result

Thus, the moment of inertia about the axis passing through the centers and perpendicular to the plane of one of the rings is:

  • I_total = 2 * m * r²

This result shows that the combined effect of the two rings contributes to the overall moment of inertia, effectively doubling the value of a single ring's moment of inertia about that axis. This principle is crucial in understanding how multiple objects interact in rotational dynamics.