two particles A & B are initially located at same point in uniform gravitational field of earth.at a certain moment they are projected with speeds v1 & v2 horizontally in opposite directions.the separation between them at a moment when their velocity vector become perpendicular to each other is??

Question

Mukesh Sharma · Answer

Here,

Initial velocity of the first projectile = v₁

Initial velocity of the 2nd projectile = v₂

Angle of projection of first projectile = 0⁰

Angle of projection of first projectile = 180⁰

(Since both are horizontal projectiles)

Horizontal displacement of the first projectile x₁= v₁t

Horizontal displacement of the 2nd projectile x₂= -v₂t

Thanks & Regards
Mukesh Sharma
askIITians Faculty

Arun Kumar · Answer

horizontal velocity of particle will remain same -v1i,v2i verticle velocity -gt,-gt taking dot product we get t^2=v1*v2/g^2

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two particles A & B are initially located at same point in uniform gravitational field of earth.at a certain moment they are projected with speeds v1 & v2 horizontally in opposite directions.the separation between them at a moment when their velocity vector become perpendicular to each other is??

two particles A & B are initially located at same point in uniform gravitational field of earth.at a certain moment they are projected with speeds v1 & v2 horizontally in opposite directions.the separation between them at a moment when their velocity vector become perpendicular to each other is??

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