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two particles A & B are initially located at same point in uniform gravitational field of earth.at a certain moment they are projected with speeds v1 & v2 horizontally in opposite directions.the separation between them at a moment when their velocity vector become perpendicular to each other is??

two particles A & B are initially located at same point in uniform gravitational field of earth.at a certain moment they are projected with speeds v1 & v2 horizontally in opposite directions.the separation between them at a moment when their velocity vector become perpendicular to each other is??

Grade:12

2 Answers

Mukesh Sharma
askIITians Faculty 43 Points
7 years ago

Here,

Initial velocity of the first projectile = v1

Initial velocity of the 2nd projectile = v2

Angle of projection of first projectile = 00

Angle of projection of first projectile = 1800

(Since both are horizontal projectiles)

Horizontal displacement of the first projectile x1 = v1t

Horizontal displacement of the 2nd projectile x2 = -v2t


Thanks & Regards
Mukesh Sharma
askIITians Faculty

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
7 years ago
horizontal velocity of particle will remain same
-v1i,v2i
verticle velocity
-gt,-gt
taking dot product we get t^2=v1*v2/g^2

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