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Two metal spheres A and B of radius r and 2r whose centres are separated by a distance of 6r are given charge Q, are at potential V1 and V2. Find the ratio of V1/V2. These spheres are connected to each other with the help of a connecting wire keeping the separation unchanged, what is the amount of charge that will flow through the wire?

Manvendra Singh chahar , 11 Years ago
Grade Upto college level
anser 3 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
VA=V1=kq/r
VB=V2=kq/2r
V1/V2= 2/1
This would be the ratio.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

Elvis Sam

Last Activity: 4 Years ago

Dear Student,
 
VA = V1 = kq/r + kq/6r
             = 7kq/6r
 
VB = V2 = kq/2r + kq/6r
             = 2kq/3r
 
V1/V2 = 7/4
 
Ratio = 7:4
 
 

saransh jain

Last Activity: 4 Years ago

Here,
 
VA=V1=kq/r

VB=V2=kq/2r

V1/V2= 2/1
 
so the ratio = 2:1
 
This would be the ratio.

Regards 
Saransh Jain

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