Two light springs of force constants k1 and k2 each 3.2

Question

Two light springs of force constants k1 and k2 each 3.2 Nm-1 and a block of mass 200g are in one line AB on a smooth horizontal table such that one end of the each spring is fixed on a rigid support and the other end is free as shown fig. The distance CD between the free ends of a spring is 60cm. If block moves along AB with a velocity 120 cm/s in between the springs, the period of oscillations of the block is ?

Vikash Tiwari · Accepted Answer

Let us consider body will start oscillation from point C ,b/w C and D.First calculate time b/w C and D V=120cm/sec displacement= 60cm Therefore time(CD)=60/120=1/2Same as above time (DC)=1/2NowTotal Time PeriodT=T/2+t(CD)+T/2+t(DC) T=2π√m/k1/2 . +1/2 . +2π√m/k2/2 +1/2T=2π(√m/k1+√m/k2)/2+1/2+1/2 T=π{√m/k1+√m/k2}+1 T=3.14(√0.2/1.8+√0.2/3.2)+1T=3.14(√1/9+√1/16)+1T=3.14(1/3+1/4)+1T=3.14×7/12+1T=1.83+1T=2.83T

General Physics> Two light springs of force constants k1 a...

Hrishant Goswami , 11 Years ago

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General Physics> Two light springs of force constants k1 a...

Hrishant Goswami , 11 Years ago

Vikash Tiwari

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