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`        Two identical particles are projected horizontally in oppositedirections with a speed of 5 ms−1 each from the top of a talltower as shown. Assuming g = 10 ms−2, the distance betweenthem at the moment when their velocity vectors become mutuallyperpendicular is(A) 2.5 m (B) 5 m (C) 10 m (D) 20 m`
4 years ago

Arun Kumar
IIT Delhi
256 Points
```							Hellov1=5i-gtjv2=-5i-gtjv1.v2=-25+(gt)^2=0=>gt=5=>t=0.5secget distance using kinematics formulae.Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
```
4 years ago
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