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Grade: 10
        
Two identical particles are projected horizontally in oppositedirections with a speed of 5 ms−1 each from the top of a talltower as shown. Assuming g = 10 ms−2, the distance betweenthem at the moment when their velocity vectors become mutuallyperpendicular is(A) 2.5 m (B) 5 m (C) 10 m (D) 20 m
4 years ago

Answers : (1)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							Hello
v1=5i-gtj
v2=-5i-gtj
v1.v2=-25+(gt)^2=0
=>gt=5
=>t=0.5sec
get distance using kinematics formulae.
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
4 years ago
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