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Two identical metallic spheres having unequal opposite charges are placed at a distance of 0.50m apart in air. After bringing them in contact with each other they are again placed at the same distance apart. Now the force of repulsion between them is 0.108N. Calculate the final charge on each of them?

Ranbir , 7 Years ago
Grade 12
anser 1 Answers
deepak

Last Activity: 7 Years ago

on bringing them in contact redistribution of charges takes place and they tend to get equal charge in the end
 
let the charge finally acquired by each of them be q
 
threrefore,
 
F= [9*109*q2] / 0.52 = 0.108
 
therefore q= \sqrt{3} × 10-6  C
 
hope this was usefull XD
 
 
 

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