Two identical metallic spheres having unequal opposite charges are placed at a distance of 0.50m apart in air. After bringing them in contact with each other they are again placed at the same distance apart. Now the force of repulsion between them is 0.108N. Calculate the final charge on each of them?
Ranbir , 7 Years ago
Grade 12
1 Answers
deepak
Last Activity: 7 Years ago
on bringing them in contact redistribution of charges takes place and they tend to get equal charge in the end
let the charge finally acquired by each of them be q
threrefore,
F= [9*109*q2] / 0.52 = 0.108
therefore q= × 10-6 C
hope this was usefull XD
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