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Grade 11General Physics

Two cells E1 and E2 in the given circuit diagram have an emf of 5 V and 9 V and internal resistance 0.3ohm and 1.2ohm of respectively.

Profile image of tanisha singh
12 Years agoGrade 11
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1 Answer

Profile image of Naman
8 Years ago
Total emf =9-5=4v
Total resistance=1+0.5+4.5+2=8
Current I in circuit. =4/8=.5A
In resistance of 3A current is =6×.5/6+3=.33A.