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two cars are moving in same direction.1st car is accelerating constantly from rest at 2 m/s^2 and 2nd car is moving with velocity of 8m/s.(left to right)the distance between 1 st and 2 nd car is 50m.At what time will the cars meet and at what distance from their initial positions?

two cars are moving in same direction.1st car is accelerating constantly from rest at 2 m/s^2 and 2nd car is moving with velocity of 8m/s.(left to right)the distance between 1st and 2nd car is 50m.At what time will the cars meet and at what distance from their  initial positions?

Grade:12

3 Answers

Shailendra Kumar Sharma
188 Points
6 years ago
Car first started with 2m/s2 whereas 2nd car is moving with 8m/s
Now 50m is the distace between the car
so the relative velocity b/w both of them is 8m/s and relative accelaration is 2m/s2
s=ut+ ½ at2 
50= 8t+(1/2)2t2
t2+8t-50=0
=> t2+10t-2t-50=0
=>t=2,-10
so time will be 2 sec
Shivam
12 Points
6 years ago
If u don`t want to do with relative motion u can also do this question by this methodMark two car one is behind the other name them A and B Let A is first car and B is second car.A is moving with constant acceleration of 2m/s^2. And B is moving with velocity 8 m/s.Let a point C where they meet and meet after t second s.Displacement of A = 50m + displacement of B .Displacement of A = ut +1/2 at^2 As A is moving with constant acceleration then u = 0 for A. Now,Displacement of A = 0 +1/2 ×2×t^2=t^2.Displacement of B = ut +1/2at^2 acceleration for B will be zero.Displacement of B = 8 ×t +0 =8tAs I tell above disp. Of A = 50 + disp. Of B t^2 = 50+ 8tt^2 -8t - 50 =0By solving get ur answer.For second part Put the value of t in displacement of AandB u get ur second answer
Shivam
12 Points
6 years ago
I have put space between lines but it is showing different and in answer 1 factor r wrong in equation of t

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