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Two bodies of mass m1 amd m2 are separated by a distance x.What is the gravitational potential at the point where gravitational field is zero?

ARADHANA , 7 Years ago

Grade 11

2 Answers

Eshan

Last Activity: 6 Years ago

Let the distance of that point from $m_1$ be $r$ .

Since gravitational field at that point is zero,

$\dfrac{Gm_1}{r^2}=\dfrac{Gm_2}{(x-r)^2}$
$\implies \dfrac{r}{x-r}=\sqrt{\dfrac{m_1}{m_2}}$
$\implies r=(\dfrac{\sqrt{m_1}}{\sqrt{m_1}+\sqrt{m_2}})x$

The gravitational potential at this point is $-\dfrac{Gm_1}{r}-\dfrac{Gm_2}{x-r}=-\dfrac{G}{x}(\sqrt{m_1}+\sqrt{m_2})^2$

Gitanjali Rout

Last Activity: 6 Years ago

$-\dfrac{Gm_1}{r}-\dfrac{Gm_2}{x-r}=-\dfrac{G}{x}(\sqrt{m_1}+\sqrt{m_2})^2$ The gravitational potential at this point is $\implies r=(\dfrac{\sqrt{m_1}}{\sqrt{m_1}+\sqrt{m_2}})x$ $\implies \dfrac{r}{x-r}=\sqrt{\dfrac{m_1}{m_2}}$ $\dfrac{Gm_1}{r^2}=\dfrac{Gm_2}{(x-r)^2}$ .Since gravitational field at that point is zero, $r$ be $m_1$ Let the distance of that point from

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