Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36g and it`s density is 9gm/cm^3 . If the mass of the other is 48g, it`s density in g/cm^3 is. {please provide the whole solution with answer}

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soham pramod javheri · Answer

As bodies are in equilibrium, 36*9=48*x density of object with 48g is x. Therefore. density of object is 36*9/48 gm/cm^3..........good luck..dude.. ​ ​ ​ ​

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Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36g and it`s density is 9gm/cm^3 . If the mass of the other is 48g, it`s density in g/cm^3 is. {please provide the whole solution with answer}

Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36g and it`s density is 9gm/cm^3 . If the mass of the other is 48g, it`s density in g/cm^3 is. {please provide the whole solution with answer}

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Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36g and it`s density is 9gm/cm^3 . If the mass of the other is 48g, it`s density in g/cm^3 is. {please provide the whole solution with answer}

Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36g and it`s density is 9gm/cm^3 . If the mass of the other is 48g, it`s density in g/cm^3 is. {please provide the whole solution with answer}

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