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Tomorrow is my physics boards exam. So please solve all parts of this question and tell me. Please fast..
Let the image distance be denoted as “v” cm. Using the general equation of refraction through a curved surface,[µ₂/v] – [µ1/u] = [(µ2 - µ1)/R]Substituting the given values, we get[1/v] – [-(3/2)/20] = [(1 – 3/2)/20]⇒ 1/v = - [3/40] – [1/40]⇒ 1/v = [-3-1]/40⇒ 1/v = -4/40⇒ 1/v = - 1/10⇒ v = - 10 cmThus, the flower appears to be 10 cm above its actual position.
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