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three particles start moving from the origin at the same time. Particle 1goes in x-direction with velocity 2m/s and 2nd in negative y-direction with 6m/s. find the velocity of the third particle along x= y line so that the three particles may always lie in a straight line three particles start moving from the origin at the same time. Particle 1goes in x-direction with velocity 2m/s and 2nd in negative y-direction with 6m/s. find the velocity of the third particle along x= y line so that the three particles may always lie in a straight line
Find the distance at any time taken as cinstant suppose take t = 1 sand then we can caluclate velocity later on..For x – axis,x = V1For y-axisy = V2for y=x,x0 = V3cos45 and y0 = V3sin45Now U have two points.(x,y) and (x0 , y0)Find the eqn. of line using this and find the intersection point with y=x. You will get V3= √2*v2v1/(v2+v1)hence V3 = 1.414* 6* 2/ (6+2)= 16.968/8 = 2.121 m/sec
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