Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
three particles start moving from the origin at the same time. Particle 1goes in x-direction with velocity 2m/s and 2nd in negative y-direction with 6m/s. find the velocity of the third particle along x= y line so that the three particles may always lie in a straight line
Find the distance at any time taken as cinstant suppose take t = 1 sand then we can caluclate velocity later on..For x – axis,x = V1For y-axisy = V2for y=x,x0 = V3cos45 and y0 = V3sin45Now U have two points.(x,y) and (x0 , y0)Find the eqn. of line using this and find the intersection point with y=x. You will get V3= √2*v2v1/(v2+v1)hence V3 = 1.414* 6* 2/ (6+2)= 16.968/8 = 2.121 m/sec
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -