This question is from vector chapter.please solve it in detail and please attach it for my convenience.
This question is from vector chapter.please solve it in detail and please attach it for my convenience.
Umar , 7 Years ago
Grade 11
General Physics> This question is from vector chapter.plea...
1 AnswersSaurabh Koranglekar
R^2 = P^2 + Q^2 + 2PQ cos θ where θ is the angle between P & Q.
3 Q^2 = P^2 + Q^2 + 2PQ cos θ
2 Q^2 = P^2 + 2PQ cos θ ——————-1
Angle between R and P is π/6
sin π/6 = (1/2) = Q sin θ / R = Q sin θ /( Q √3)
sin θ = √3 /2 => cos θ = (1/2)
From 1
2 Q^2 = P^2 + PQ
P^2 + PQ - 2 Q^2= 0
P = Q and P =- 2 Q
3 Q^2 = P^2 + Q^2 + 2PQ cos θ
2 Q^2 = P^2 + 2PQ cos θ ——————-1
Angle between R and P is π/6
sin π/6 = (1/2) = Q sin θ / R = Q sin θ /( Q √3)
sin θ = √3 /2 => cos θ = (1/2)
From 1
2 Q^2 = P^2 + PQ
P^2 + PQ - 2 Q^2= 0
P = Q and P =- 2 Q
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