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This question is from vector chapter.please solve it in detail and please attach it for my convenience.

This question is from vector chapter.please solve it in detail and please attach it for my convenience.

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Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
R^2 = P^2 + Q^2 + 2PQ cos θ where θ is the angle between P & Q.

3 Q^2 = P^2 + Q^2 + 2PQ cos θ

2 Q^2 = P^2 + 2PQ cos θ ——————-1

Angle between R and P is π/6

sin π/6 = (1/2) = Q sin θ / R = Q sin θ /( Q √3)

sin θ = √3 /2 => cos θ = (1/2)

From 1

2 Q^2 = P^2 + PQ

P^2 + PQ - 2 Q^2= 0

P = Q and P =- 2 Q

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