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Grade 11General Physics

This question is from projectile motion. Solve using formula.

Question image for This question is from projectile motion. Solve us
Profile image of Umar
7 Years agoGrade 11
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer7 Years ago
Along vertical 
v = u + at
vSinθ’ = uSinθ - gt
vSinθ’ = 30*1/2 - 10*1.5
vSinθ’ = 15 - 15 = 0
Sinθ’ = 0
θ’ = 0°

Angle made by the velocity vector with horizontal after 1.5s is 0°