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Grade 12General Physics

There is a derivation given in my book which concludes to the fact that the range is same for two angles of projection, provided they are complementary. I fail to understand this fact. For example, what if we put the angle as 90 and 0 which are complimentary.practically how is the particle projected at zero degree have 0 range?isnt rolling a ball on a floor have a range?or maybe hitting the ball during billiards. Basically at zero degree I feel the motion would become rectilinear.whereas at 90 degree the range is zero as the object goes up and comes down. I have understood it mathematically by putting the angles in the range formula but not practically. Please help

Profile image of Jai Mahajan
11 Years agoGrade 12
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1 Answer

Profile image of Shivam
11 Years ago
Range is the horizontal displacement by projectile in the time in which the body is above the horizontal level(ground).Or we can say Range = orizontal component of velocity x T..,where T is the the time taken by body to go up and come down.In case of 00 projection angle vertical displacement is 0 so the time taken by projectile (T) to go up and come down is also 0 . Thus ,range becomes 0.When released at an angle of 900 horizontal component of velocity becomes 0 ,thus range becomes 0 .