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There are 2 wires of same material. Their radii & lengths are both in the ratio 1: 2. If the extensions produced are equal, what is the ratio of the loads?
let l1 be the extension in wire 1 then,l1 = Fl/YAand l2 be the extension in wire 2 then,l2 = F’l’/YA’Now Given, l1 = l2hence,Fl/YA = F’l’/YA’F/F’ = Al’/A’l = (pi*r^2)*(2l)/(pi*4*r^2)*(l) = 2/4 = ½
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