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`        the velocity v of a body moving along a straight line varies with time t as v= 2t2e-t , where v is in m/s and t in sec. The acceleration of body is 0 at t=1)02)23)34)both (1) and (2)`
5 years ago

bharat bajaj
IIT Delhi
122 Points
```							v= 2t2e-t .....a = dv/dt = 2. ( -t^2. e^(-t) + e^(-t).2t) = 2.t.e^(-t) ( 2 - t) .....Hence, a = 0 at t = 0 and t = 2 s....Option 4) is correct....THanks..Bharat Bajaj...IIT Delhiaskiitians faculty
```
5 years ago
Arun Kumar
IIT Delhi
256 Points
```							Hello$\\ \\v=2t^2e^{-t} \\a={dv \over dt} \\=e^{-t}(4t-2t^2) \\put the value to get the answer$Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
```
5 years ago
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